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Precalculus
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Can anyone help me out with this? Find the inverse of the function. f(x) = 6x3 + 3
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Put y=6x3+3 Then solve for x
How would i solve for x?
jst find the value of x in the terms of y where y = f(x) thus \[y = 6x ^{3} + 3\] and thus u will get \[x= \sqrt[3]{\frac{ y }{ 6 } - \frac{ 1 }{ 2 }}\]
Then don't you have to write back in terms of f^(-1) x such as \[f ^{-1}(x)=\sqrt[3]{\frac{ x }{ 6 }-\frac{1}{2}}\]
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