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The length of a diagonal of a square is 7 inches. Find the perimeter of the square. A. 25 inches B. 12 inches C. 19.6 inches D. 28 inches
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7 is the hypotenuse in the following isosceles right triangle: So, a^2 + b^2 = c^2 -> 2a^2 = 7^2 -> a = 7 / [sqrt(2)] P = 4a = 4 times 7 / [sqrt(2)] = (14)[sqrt(2)]|dw:1369322852303:dw|
So, 14 x sqrt of 2?
That triangle is part of:|dw:1369322947638:dw| Yes, 14 times sqrt(2)
19
Yes! (rounded) It's actually 19.798989873223330683223642138936
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