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The sum of the interior angles of a polygon is 540°. How many sides does the polygon have? i would like to know how to do this also
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For all polygons, the sum if the interior angles is equal to (n-2)*180 degrees where n is the number of sides. So set 540=(n-2)180 div by 180 3=n-2 add 2 n=5 The polygon has 5 sides.
OK that helps ALOT. Thanks for your help! :)
How many degrees are there in an interior angle of a regular 6-sided polygon?
Remember (n-2)*180 so set n=6 (6-2)*180 4*180 720
Oh OK so i already know the formula and know that 6 is n, then i can just insert 6 for n and then work the problem out?
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Yep
alrighty thanks!
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