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Precalculus
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Find all x-intercepts and y-intercepts of the graph of the function. F(x)= x^3 - x^2 -9x +9
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x= (3,0),(-3,0),(1,0) y= (0,9)
find the y-intercept by putting x = 0 in your function
That comes out to 9 right?
twigo2 - dont just give him the answer - show him how to solve the problem
yes so y-intercept is the point (0.9)
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(0,9)
Okay thanks, I'm just not sure how to find the x intercept if there If there is no y value
Woops sorry for my wording.
you need to solve the equation x^3 - x^2 - 9x + 9 = 0
Oh I see, I got it!
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Thank you!
one clue to this is since the last number is + 9 so x = 3 and x = -3 are possible values of the intercepts
yw
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