MEDAL AND FAN!!!! Carmen is purchasing hamburgers and chips for a party. A bag of chips costs $2 each and hamburgers cost $4 per pound. She must spend less than $50. Carmen will be buying at least six pounds of hamburgers. Which of the following is a solution for Carmen? A. 10 bags of chips and 8 pounds of hamburger B. 10 bags of chips and 7 pounds of hamburger C. 13 bags of chips and 6 pounds of hamburger D. 15 bags of chips and 5 pounds of hamburger
C, since it says "she will be buying 6 pounds of hamburgers" include that as a given. === 6 pounds X $4 per pound = $24 and the remaining of the money is $26 === $26 / $2 = 13 bags of chips anyone can correct me, i might be wrong :D
C
William got $150 for making all A’s on his report card. He wants to spend it on CDs and DVDs. The local video store is having a sale; all CDs are $10 and all DVDs are $15. Which of the following is a possible combination of CDs and DVDs? A. 2 CDs and 9 DVDs B. 7 CDs and 5 DVDs C. 8 CDs and 6 DVDs D. 11 CDs and 3 DVDs
last one you guys!
B, all you have to do is just multiply the number of CD/DVD by the cost. For me, basically it's trial and error since you're given the number of CDs and DVDs. === 7 CDs X $10 = $70 === 5 X $15 = $75 Just add all the cost, this gives you $145. Therefore, you have a remaining of $5 (maybe you could spend it for some ice cream for me lol).
thaks lynn!!!!!!!!!!!!
;) you're welcome
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