Question

AB is tangent to O. If AO = 12 and BC = 25, what is AB? The diagram is not to scale.

Answer 1

@RadEn

Answer 2

AB^2 = BO^2 - AO^2
AB^2 = (BC+CO)^2 - AO^2
AB^2 = (25+12)^2 - (12)^2
AB^2 = (37)^2 - (12)^2
AB^2 = (37+12)(37-12)
AB^2 = (49)(25)
AB = sqrt(49 * 25) = sqrt(49) * sqrt(25) = 7 * 5 = 35

Answer 3

but i dont see that as a choice

Answer 4

maybe, just in sqrt form right ?

Answer 5

oh wait i just got it

Answer 6

i have a couple more could you help me with them?

Answer 7

sorry, i have to go now. next time i will be back to joining again :)

Answer 8

okay well thank you