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OpenStudy (anonymous):
how would I solve (x+2)^2=1??? And what would the answer be??
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OpenStudy (anonymous):
Expand, then bring the 1 over the other side. Factor the this final quadratic and get the values of x.
OpenStudy (anonymous):
\[x ^{2}+4x+4=1\]
OpenStudy (anonymous):
\[x ^{2}+4x+3=0\]
OpenStudy (anonymous):
I got x=-1 and -3?
OpenStudy (anonymous):
\[(x+1)(x+3)=0\]
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OpenStudy (anonymous):
cool @laurenh22
OpenStudy (anonymous):
now give me some love @laurenh22
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