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OpenStudy (anonymous):
Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).
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OpenStudy (tkhunny):
Well, do it! First, find the center. Second, determine the orientation.
OpenStudy (anonymous):
@tkhunny I need help with it! I think I got it to y^2/36 - x^2/81 = 1 ??
OpenStudy (tkhunny):
Good try, but no. Did you decide on a Major Axis? How did you decide the denominator on x? Where is the minor axis?
OpenStudy (tkhunny):
BTW "y^2/36" is good.
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