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Well each graph has the correct minimum...and maximum....all but 1 graph have the median correct...After that...to figure out which of the 3 remaining graphs contain the correct bounds...you basically find the median again.....but only caring about numbers > the median and < the max....for the right bound........and < the median and > the min for the left bound so minimum = 11 maximum = 29 median = 19 *eliminates C Now...what is the median of 21, 23, 24, 29 for the right bound? and what is the median of 11, 13, 16, 18 for the left bound?
is it a ?
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it is indeed :)
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Thank You Again.
again no problem :)
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