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ganeshie8 (ganeshie8):
do you have a pic wid this q... ?
OpenStudy (anonymous):
yeah hold on
ganeshie8 (ganeshie8):
ok :)
OpenStudy (anonymous):
OpenStudy (anonymous):
thats the pic
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ganeshie8 (ganeshie8):
for any circle, a tangent makes 90 degrees with the radius
ganeshie8 (ganeshie8):
since BDC = 45, can you find ADB ?
OpenStudy (anonymous):
ADB is the same as DAB isnt it
OpenStudy (anonymous):
you can verify this with the sine law.
\[\frac{ a }{ sinA } = \frac{ b }{ sinB } = \frac{ c }{ sinC }\]
for a triangle ABC, where a is the length of the side opposite of angle A.
|dw:1369373133655:dw|
since BC and CD are the same length (radius of circle) their angle are are the ame implying that < BCD = < ABD = 90
OpenStudy (anonymous):
are the same which implies that *
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OpenStudy (anonymous):
so DAB is 90
OpenStudy (anonymous):
yes since < BCD and < BDC are 45 and the angles of a triangle sum to 180