Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

given ab and ad are tangent of c and the m

ganeshie8 (ganeshie8):

do you have a pic wid this q... ?

OpenStudy (anonymous):

yeah hold on

ganeshie8 (ganeshie8):

ok :)

OpenStudy (anonymous):

OpenStudy (anonymous):

thats the pic

ganeshie8 (ganeshie8):

for any circle, a tangent makes 90 degrees with the radius

ganeshie8 (ganeshie8):

since BDC = 45, can you find ADB ?

OpenStudy (anonymous):

ADB is the same as DAB isnt it

OpenStudy (anonymous):

you can verify this with the sine law. \[\frac{ a }{ sinA } = \frac{ b }{ sinB } = \frac{ c }{ sinC }\] for a triangle ABC, where a is the length of the side opposite of angle A. |dw:1369373133655:dw| since BC and CD are the same length (radius of circle) their angle are are the ame implying that < BCD = < ABD = 90

OpenStudy (anonymous):

are the same which implies that *

OpenStudy (anonymous):

so DAB is 90

OpenStudy (anonymous):

yes since < BCD and < BDC are 45 and the angles of a triangle sum to 180

OpenStudy (anonymous):

thank you (:

OpenStudy (anonymous):

glad i could help :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!