Question

I multiply two consecutive numbers and get a product of 1122. What are the two numbers?

Answer 1

First find the square root of 1122.

The 2 numbers will surround the number you got as the root.

Answer 2

let the first number be \(n\)
the other number is consecutive so it is \(n+1\)

\[(n)\times(n+1)=1122\\n^2+n-1122=0\]


apply the quadratic formula

\[ax^2+bx+c=0\]
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]


NB; there will be two solutions

Answer 3

Hello @Xcresent , great to see you here on OS .

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