a man cover 27kms in 9hours abd return home with a speed of 5km/hr.what is his average speed for entire journey

Question

mayankdevnani · Answer

first of all. what is the speed at first situation, given that , d=27km and t=9hr and can you find the speed??

mayankdevnani · Answer

$$\huge speed=\frac{distance \space travelled}{time \space taken}$$

mayankdevnani · Answer

can you now solve it!!   @qaiser380

anonymous · Answer

for average speed there is a simple relation

 av. speed  = v = total distance travelled/ total time taken
and hence the average speed would be 27/9 = 3 km/hr
and in SI system 0.833... m/s

anonymous · Answer

He goes with a speed of 27/9 = 3km/hr.

He returns with a speed of 5km/hr.

So his average speed = (3+5)/2 = 4km/hr.

mayankdevnani · Answer

@rijusarkarr      plzz don't give direct answers. let  @qaiser380  be understand!