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write the line that passes through (-1,5) with aslope of 2 in standard form
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slope = \[\frac{ y -y _{1}}{ x-x _{1} }\] where slope = 2, \[y _{1} = 5\] and so\[y-5 = 2(x+1)\] and so y = 2x +7
Use the point-slope form \(y-y_1=m(x-x_1)\) Where \((x_1,y_1)\) and slope = m
oh okay
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