can you check my answer?
An auditorium earned $25,000 in sold−out concert ticket sales. Front section tickets cost $75 per seat and back section tickets cost $50 per seat. The number of front section seats is twice the number of back section seats. How many seats are in the front section?
i think its 250
Please demonstrate your methodology.
25000 = 50X + (2)75X 25000 =200X X = 125
Then do the ratio of 2:1 Front = 250 Back = 125
Hmmm... It seems a little magic. Translate the problem statement more directly. F = # of seats in the front section B = # of seats in the back section Please provide clear and sufficient definitions. This will save you. "The number of front section seats is twice the number of back section seats." 1) F = 2B "An auditorium earned $25,000 in sold−out concert ticket sales. Front section tickets cost $75 per seat and back section tickets cost $50 per seat." 2) 50B + 75F = 25000 "How many seats are in the front section?" Substitute from 1) into 2) 50B + 75(2B) = 25000 Solve and finish. 50B + 150B = 25000 200B = 25000 2B = 250 B = 125 Using Equation 1), we have: F = 2(125) = 250 Checking: 125(50) + 250(75) = 6250 + 18750 = 25000 You do have the correct answer, but the fact that you asked to have it checked suggests you are missing some confidence. Just be a little more deliberate. Use my work as an example of a clean, understandable, correct, and reproducible methodology that will build your confidence.
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