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Mathematics
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AC II ED. Solve for x, round to the nearest tenth
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x = 6 x = 37.5 x = 21.7 x = 42.5
try seting up a proportion
I Did That. 10(8)=3(x+5) But The Answer I Get Isn't One Of The Answer Choices.
ok, below is how to set it up :- \(\large \frac{x-5}{10} = \frac{25}{15}\) \(\large \frac{x-5}{10} = \frac{\cancel{25}^5}{\cancel{15}^{3}}\) \(\large \frac{x-5}{10} = \frac{5}{3}\) \(3(x-5) = 5(10)\) \(3x-15) = 50\) \(3x = 65\) \(x = ?\)
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:O Ohhhh Okay. I See What I Did Wrong. Thanks.
good :)
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