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Mathematics 27 Online
OpenStudy (anonymous):

AC II ED. Solve for x, round to the nearest tenth

OpenStudy (anonymous):

OpenStudy (anonymous):

x = 6 x = 37.5 x = 21.7 x = 42.5

ganeshie8 (ganeshie8):

try seting up a proportion

OpenStudy (anonymous):

I Did That. 10(8)=3(x+5) But The Answer I Get Isn't One Of The Answer Choices.

ganeshie8 (ganeshie8):

ok, below is how to set it up :- \(\large \frac{x-5}{10} = \frac{25}{15}\) \(\large \frac{x-5}{10} = \frac{\cancel{25}^5}{\cancel{15}^{3}}\) \(\large \frac{x-5}{10} = \frac{5}{3}\) \(3(x-5) = 5(10)\) \(3x-15) = 50\) \(3x = 65\) \(x = ?\)

OpenStudy (anonymous):

:O Ohhhh Okay. I See What I Did Wrong. Thanks.

ganeshie8 (ganeshie8):

good :)

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