Question

(x-3)^2 +(y+4)^2=25 in polar form please help!!! Here are the choices

a) r=6cos(theta)-8sin(theta)
b) r=8sin(theta)-6cos(theta)
c) r=7/(cos(theta)*sin(theta)
d) r=4/(cos(theta)*sin(theta)

Answer 1

answer is a.

i got it by expanding the brackets, then plugging in these 3 equations:

x^2 + y^2 = r^2
x = rcos(theta)
y = rsin(theta)

Answer 2

Thank you!!