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Find the product. (n^3)^2 · (n^5)^4
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You need two properties of exponents: \[(x^a)^b = x^{a*b}\]and\[x^a*x^b = x^{a+b}\]
I just need to figure out the total power of n. The answer is n to the _ power.
n^3)^3=n^9 (multiply when an exponent has another exponent). thus, (n^4)^5=n^20 n^9*n^20=n^29 (add when multiplying exponents).
Thank you :)
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