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OpenStudy (anonymous):
what is the solution to the equation cos2x+2=sinx for 0degrees
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OpenStudy (anonymous):
Use the trig identity: cos2x=1-2(sinx)^2 1-2(sinx)^2-sinx+2=0 -2(sinx)^2-sinx+1=0 (Sinx+1)(2sinx-1)=0 Sinx=-1 or sinx=1/2 X=3pi/2 or x= pi/6 or x=5pi/6
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