Question

Please help :)

Answer 1

http://screencast.com/t/ubyaEVDr4

Answer 2

@Callisto

Answer 3

\[2^x - 2^{-x} =1\]\[2^x(2^x - 2^{-x}) =2^x(1)\]\[(2^{2x} - 2) =2^x\]\[(2^x)^2 - 2^x -2=0\]

Answer 4

why do u put them in brackets in the second step

Answer 5

I multiplied both sides by \(2^x\)

Answer 6

thts the only solution

Answer 7

Hmm?

Answer 8

thanks:)

Answer 9

Welcome :)