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OpenStudy (anonymous):
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OpenStudy (anonymous):
\[<AFE = <BFC\] \[AE \left| \right| BC\]\[\rightarrow \] \[<AEF = <FCB & <EAF = <FBC\] solved
ganeshie8 (ganeshie8):
you may use vertical angles + alternate interior angles to prove triangles are similiar by AA similarity. give it a try
OpenStudy (anonymous):
uhh, hi there sheradon :)
OpenStudy (mertsj):
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