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Mathematics 15 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

\[<AFE = <BFC\] \[AE \left| \right| BC\]\[\rightarrow \] \[<AEF = <FCB & <EAF = <FBC\] solved

ganeshie8 (ganeshie8):

you may use vertical angles + alternate interior angles to prove triangles are similiar by AA similarity. give it a try

OpenStudy (anonymous):

uhh, hi there sheradon :)

OpenStudy (mertsj):

Are you supposed to have help with a test?

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