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A beam, the weight of which may be neglected, is supported by three identical springs. When a weight W is hung from the middle of the beam, the extension of each spring is x. Click to see diagram: http://i164.photobucket.com/albums/u32/Codefusionlab/Springs.jpg The middle spring and the weight are removed. What is the extension when a weight of 2W is hung from the middle of the beam?
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let the extension in all the springs be x therefore kx=mg kx=10w x=10w/k
The answer is 3x
no it will be 2x
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