The width and area of a rectangle are shown in the figure. What is the length of the rectangle.
W= (2b-1)in
A=(4b^3 +5b - 3)in^2

Question

The width and area of a rectangle are shown in the figure. What is the length of the rectangle.
W= (2b-1)in
A=(4b^3 +5b - 3)in^2

anonymous · Answer

(4b^3 + 5b - 3)/(2b - 1) = L

because   (A)rea / (W)idth = (L)ength

(4b^3 + 5b - 3)/(2b - 1) = 2b^2 + b + 3

Do you need to see the long division?

anonymous · Answer

yeah because im still a little confused with it

anonymous · Answer

np, my connect speed is slow, but I'll move along.

anonymous · Answer

ok

anonymous · Answer

|dw:1369522709789:dw|

anonymous · Answer

That first line subtracted got a little overlaid.  It should look like:

4b^3  -  2b^2

Look closely and you'll see the "^" mixed in with the b

anonymous · Answer

so to check my answer i multilply 2b-1 with 2b^2 +b +3
Got it

anonymous · Answer

You got it!  Good job!

anonymous · Answer

:)) sorta gettin easy as pie

anonymous · Answer

It will take a little practice and a little of the "I can do it" spirit!

anonymous · Answer

haha true. thanks :)

anonymous · Answer

Just think of Math as a friend that sometimes speaks a foreign language!

anonymous · Answer

uw!  And thx for the medal!

anonymous · Answer

haha no problem :)