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\[\large R= \frac{ 575x }{ \sqrt{x} }-3x\]
575/2sqrtx -3
how?
first divide x by sqrt x , you will get sqrt x, so R=575sqrtx -3x, the derivation of sqrtx is 1/(2sqrtx) and 3x is 3 , so R'=575/(2sqrtx) -3
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