Barry deposited $4000 into two saving accounts bearing simple interest. One of the accounts has an interest rate of 10% while the other rate is 4%. If the total interest earned after one year is $352, find the amount deposited into each of the accounts.

Question

anonymous · Answer

let his savings in the accounts be x and 4000-x   then the interest on 1 yr 
from the are respectively 10x /100 and 4*(4000-x)/100
hence by the problem 
we have x/10 +(16000-4x)/100=352
or x/10 +160 -4x/100 =352
or (10x-4x)/100 =352-160
or 6x/100=192
or x=192/6 *100=3200
thus he invested 3200 in 10% account and (4000-3200)=800  in  4%