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(5i)/(2-3i√(3)
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first multiply both num and deenum by (2+3i√(3)
thus we have (5i)/(2-3i√(3) =(5i) *(2+3i√(3) / (2+3i√(3)(2-3i√(3) =10i +15√(3) *i^2) /(4- 27*i^2 ) = (10i -15√(3))/31
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