An object which is vertically projected or falls from the sky has a velocity of 'v' and is given by: v = -32t + vo, where 'v' is the velocity in feet/sec, 't' is the time in seconds, and 'vo' is the initial velocity in feet per second. If the initial velocity is 195 feet/sec, and the velocity v is in the range of 3

Question

An object which is vertically projected or falls from the sky has a velocity of 'v' and is given by: v = -32t + vo, where 'v' is the velocity in feet/sec, 't' is the time in seconds, and 'vo' is the initial velocity in feet per second. If the initial velocity is 195 feet/sec, and the velocity v is in the range of 3 < v < 99, find the time interval t.

allank · Answer

Nice single variable calculus

anonymous · Answer

$$3<t <6$$

anonymous · Answer

v=-32t+195 3 <-32t+195< 99 192 <-32t <-96 or -6<-t<-3 or 6>t>3i.e the reqd interval is 3

zzr0ck3r · Answer

v = -32t+195 
solve for 3 = -32t+195 and 99 = -32t+195