log subscript x+3(x^3+x-2/x)=2 solve for x
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solve for x
OK Now if you remove the you know |dw:1369589010329:dw|
@rajee_sam ATTENTION above you have wrote -3 when there is -2
if you expand both sides x ( x + 3)² = x³ + x -3 x ( x² + 6x + 9) = x³ + x -3 x³ + 6x² + 9x = x³ + x - 3 combine like terms 6x² + 8x + 3 = 0 Now solve this quadratic
6x² + 8x + 2 = 0
TY @jhonyy9
yw
yes Log subscript (x+3)
need help solving quadratic
i do , just need help solving
@rajee_sam please help solve quadratic
write it here
b^2-4ac
i got x=-1 tho
You can use quadratic formula or you can solve by facoring
3, but cancelled 3 because it doesnt work when i check.
so its wrong ?
since I suggest you use discriminant, and you come up with that, go ahead, but if it s too hard, you can apply rajee.sam way, factor. it's ok,
show me your work, you are my tutor, I know how to check, I don't know how to work, hihi.
i used factoring so 6x^2 +8x+2 =0 is 2(3x^2+4x+1)=0
then 2(x-3) (x+1) , then put both in equal to zero
let 2 aside, how do you get (x-3)(x+1) expand them, you don't get 3x^2 +4x+1 redo, please
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