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Mathematics 14 Online
OpenStudy (anonymous):

log subscript x+3(x^3+x-2/x)=2 solve for x

OpenStudy (rajee_sam):

|dw:1369588679557:dw|

OpenStudy (anonymous):

solve for x

OpenStudy (rajee_sam):

OK Now if you remove the you know |dw:1369589010329:dw|

jhonyy9 (jhonyy9):

@rajee_sam ATTENTION above you have wrote -3 when there is -2

OpenStudy (rajee_sam):

if you expand both sides x ( x + 3)² = x³ + x -3 x ( x² + 6x + 9) = x³ + x -3 x³ + 6x² + 9x = x³ + x - 3 combine like terms 6x² + 8x + 3 = 0 Now solve this quadratic

OpenStudy (rajee_sam):

6x² + 8x + 2 = 0

OpenStudy (rajee_sam):

TY @jhonyy9

jhonyy9 (jhonyy9):

yw

OpenStudy (anonymous):

yes Log subscript (x+3)

OpenStudy (anonymous):

need help solving quadratic

OpenStudy (anonymous):

i do , just need help solving

OpenStudy (anonymous):

@rajee_sam please help solve quadratic

jhonyy9 (jhonyy9):

write it here

OpenStudy (anonymous):

b^2-4ac

OpenStudy (anonymous):

i got x=-1 tho

OpenStudy (rajee_sam):

You can use quadratic formula or you can solve by facoring

OpenStudy (anonymous):

3, but cancelled 3 because it doesnt work when i check.

OpenStudy (anonymous):

so its wrong ?

OpenStudy (loser66):

since I suggest you use discriminant, and you come up with that, go ahead, but if it s too hard, you can apply rajee.sam way, factor. it's ok,

OpenStudy (loser66):

show me your work, you are my tutor, I know how to check, I don't know how to work, hihi.

OpenStudy (anonymous):

i used factoring so 6x^2 +8x+2 =0 is 2(3x^2+4x+1)=0

OpenStudy (anonymous):

then 2(x-3) (x+1) , then put both in equal to zero

OpenStudy (loser66):

let 2 aside, how do you get (x-3)(x+1) expand them, you don't get 3x^2 +4x+1 redo, please

OpenStudy (loser66):

|dw:1369590816077:dw|

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