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How to write a function that models a rectangle's area underneath a graph...?
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A rectangle is drawn under a parabola y=45-3x^2 such that two of its vertices are on the parabola, its base lies on the x-axis, and the rectangle is above the x-axis... Determine a function that models the rectangle's area
Area of rectangle = length * width width is along x-axis length is y-value of parabola Area = (2x)*(45-3x^2)
ohhh x_x
|dw:1369595019487:dw|
so the 4 is the equation of the graph ?
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**y
yes
but what if it looked like this |dw:1369595194853:dw|
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