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Find the area of the figure to the nearest tenth.
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Choices: 31.5 in sq 99.0 in sq 11 in sq 197.8 in sq
(140/360)*pi*9^2 = (81*7/18)pi = 99.0 in^2
I completely forgot to multiply with pi! Thanks!
area of a sector: \(A={degrees\over360}\pi r^2\)\[A={140\over360}\pi(9)^2\]solve it :)
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