Question

for questions 3 and 4, what values for theta(0 less than or equal to. theta. less than or equal to 2pi)

3. 3sin(theta) = sin(theta) -1
A. pi/3, 5pi/3

B. 2pi/3, 4pi/3

C. pi/6, 3pi/6

D. 7pi/6, 11pi/6

4. tan^2(theta) = -3/2 sec(theta)
A. pi/2, 5pi/2

B. 3pi/4, 5pi/4

C. pi/3, 5pi/3

D. 2pi/3, 4pi/3

Answer 1

Just substitute the values given and find the value of the equation and se which one satisfies the condition.

Answer 2

answered yesterday

Answer 3

im sorry but i have absolutely no idea how to do these problems..

Answer 4

\[3\sin \theta=\sin \theta-1\]
\[3\sin \theta-\sin \theta=-1\]
\[\sin \theta=\frac{ -1 }{2 }=-\sin \frac{ \pi }{ 6 }=\sin \left( \pi+\frac{ \pi }{6 } \right),\sin \left( 2\pi-\frac{ \pi }{ 6 } \right)\]
\[\theta=\frac{ 7\pi }{ 6 },\frac{ 11\pi }{ 6 }\]

Answer 5

can you help me with the other one too?

Answer 6

And thanks!