Question

verify identity: tanx+cotx=(secx)cscx

Answer 1

tanx = \[\tan x + \cot x \] \[= \frac{ \sin x }{ cosx } + \frac{ \cos x }{ sinx } \]\[= \frac{ Sin ^{2} x + Cos ^{2}x }{ Cos x. Sin x}\]\[= \frac{ 1 }{ Cos x . Sinx }\] \[= \frac{ 1 }{ Cos x } \times \frac{ 1 }{ Sin x }\]\[= Sec x . Csc x\]

Answer 2

thanks!