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^3sqrt(2x-1) differentiate
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differentiate y = log base e 3x+8x^3
\[\Large \frac{d}{dx}(\log_e(3x+8x^3))\]
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\[y = \log_e (3x+8x^3)\] Using \(\LARGE\log_ab=c \Leftarrow\Rightarrow b=a^c\), gives \[\Large 3x+8x^2=e^y\] Can you differentiate it now? it's implicit differentiation.
|dw:1369654956537:dw|
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yes
ok, the derivative of cube root of f(x) is f ' (x)/ 3 cube root of (f(x))^2 so, |dw:1369667759060:dw|
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