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OpenStudy (yrelhan4):
[2(x-2)]/3=4x.. is this the question?
OpenStudy (anonymous):
2 over 3 (x-2) = 4x for x
OpenStudy (yrelhan4):
x-2 in numerator or denominator?
OpenStudy (anonymous):
well look maybe this might help you have to find x
Solve the equation 2 over 3 (x − 2) = 4x
possible answers
2 over 5 negative
5 over 2 negative
2 over 5 positive
5
OpenStudy (aravindg):
Wait are you taking a test ?
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OpenStudy (anonymous):
no its a practice for test i need to understand how to do it and then it will help me for my real test
OpenStudy (anonymous):
so can you help me ?
OpenStudy (kenljw):
[2(x-2)]/3=4x
2x-4=12x
10x=4
x=2/5
OpenStudy (aravindg):
ok First and foremost Multiply by 3 on both sides
OpenStudy (anonymous):
yes
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OpenStudy (aravindg):
Did you understand how to get the answer?
OpenStudy (anonymous):
x= 2/5 ?
OpenStudy (aravindg):
I got -2/5
OpenStudy (aravindg):
2x-4=12x
10x=-4
x=-2/5
OpenStudy (kenljw):
yes my error
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