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Precalculus
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solve: tan^4x - 1=0
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Have you considered factoring the difference of squares?
i have but then i get something really messed up....
this is easy
nevermind i got it
your a genious
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\[(\tan ^{2}x-1)(\tan ^{2}x+1)\] =\[(tanx-1)(tanx+1)(\tan ^{2}+1)\] now tan^2x+1 can never be negetive so either tanx=1 or tanx=-1 which is possible only if x=pi/4or 3pi/4 in the interval of o to pi
i forgot to equate these with zero
do you know most girls are not good in math
wow stereotypical much?
do you know most guys are not good at anything else :P
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lol thats true :P
Really? I find that most who are not discouraged somewhere along the line do quite well in just about anything they pursue. Sex? Not significant. Age? Not significant. Ethnicity? Not significant.
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