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Help with math please! find the value of x in a triangle with length of 8, height of 6 & diagonal of 5x-4
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i assume it is a right triangle?
sorry i meant rectangle
if so you have a 6 - 8 - 10 right triangle, so \(5x-4=10\)
ok same thing
Rectangle***
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|dw:1369707289352:dw|
we know the diagonal is 10 by pythagoras \[6^2+8^2=10^2\]
how do you get 10?
pythagoras
how do you get x though
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the diagonal makes a right triangle
solve \(5x-4=10\) in two steps
add 4, divide by 5
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