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Mathematics 7 Online
OpenStudy (anonymous):

lim x->0 (1+x)(1+2x)(1+3x)-1 / x indetermiation 0/0

OpenStudy (dumbcow):

expand the top and then you will see you can factor out an "x"

OpenStudy (anonymous):

well, the factor : (1+x)(1+2x)(1+3x)-1 its hard to me

OpenStudy (anonymous):

please if you can help me

OpenStudy (dumbcow):

do it in steps

OpenStudy (dumbcow):

(1+x)(1+2x) = 2x^2 +3x +1 then do (2x^2 +3x+1)(1+3x)

OpenStudy (anonymous):

thankks!

OpenStudy (dumbcow):

yw for checking answers i recommend using this site http://www.wolframalpha.com/input/?i=lim+x-%3E0+%28%281%2Bx%29%281%2B2x%29%281%2B3x%29-1%29+%2Fx

OpenStudy (anonymous):

and the -1? after the equation

OpenStudy (dumbcow):

you will add it to the result you multiplied out

OpenStudy (anonymous):

ahh ok okokokk :)

OpenStudy (anonymous):

to factor :|dw:1369762888858:dw|

OpenStudy (dumbcow):

not quite...you didn't finish expanding (2x^2 +3x +1)(1+3x) = 6x^3 + 11x^2 +6x + 1

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