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No question.
Well aint this one a toughy
Have you calculated what the inverse of g(x) is yet?
g inverse = x^3 - 1 g(g inverse) = [(x^3 - 1) + 1]^(1/3) g(g inverse) = [x^3 + (-1 + 1)]^(1/3) g(g inverse) = [x^3 + (0)]^(1/3) g(g inverse) = (x^3)^(1/3) = x g(g inverse(-6)) = -6
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Well there ya go. :)
Good luck to you in all of your studies and thx for the recognition! @RichGrl20
@tcarroll010 : No problem, and thanks for answering my question! :D
uw!
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