Which is the equation of the circle with center (3,-5) and radius 6?
a (x+3)^2+(y-5)^2=36
b (x-3)^2+ (y+5)^2=36
c (x+3)^2+(y-5)^2=6
d (x-3)^2+(y+5)^2=6

Question

Which is the equation of the circle with center (3,-5) and radius 6?
a (x+3)^2+(y-5)^2=36
b (x-3)^2+ (y+5)^2=36
c (x+3)^2+(y-5)^2=6
d (x-3)^2+(y+5)^2=6

anonymous · Answer

your answer would have to be "b"

anonymous · Answer

Thank you.

anonymous · Answer

no problem I had to do a lesson on this a week ago  I understand how it feels when  your just learning it. the equation for a circle is (x-center point x+y- center point y) =radius squared therefor if the center point is (3,-5) and the radius is 6 (x-3+y+5)=36

anonymous · Answer

Thanks.