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How do you solve this: log base of 2 (x+4) = 3 - log base of 2 (x-2) ?
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\[\log_{2} (x+4) = 3 - \log_{2} (x-2)\]
log(x + 4) / log(2) = 3 - log(x - 2) / log(2)
Ok, but now what?
Do you want the solution?
or do you want the alternate form assuming x is positive?
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the alternate form assuming x is positive is log ((x - 2) (x + 4)) = log(8)
after this (x-2)(x+4)=8 and simply solve for x usinq quadratic formula
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