Question

Find angle between given vectors to the nearest tenth of a degree u = <15,-9>, v = <13,-22>

Answer 1

\[\cos \theta = \frac{u*v}{|u| |v|}\]
where
\[u*v = (15*13)+ (-9*-22)\]
\[|u| = \sqrt{15^{2} +(-9)^{2}}\]
|v| in same way

that should help

Answer 2

thank you so much your a life saver

Answer 3

no problem

Answer 4

so then for v I just plug in the numbers right?