Question

Solve
3x-2y=10
2x+3y=-2

Answer 1

somebody help please.

Answer 2

plase help

Answer 3

First try to cancel out any one variable by either addition or subtraction.
Let 3x-2y=10 be eqn(1) and 2x+3y=-2 be eqn(2)
To cancel out x, let's multiply eqn (1) with 2 and eqn (2) with 3
2(3x-2y)=2(10) and 3(2x+3y)=3(-2)
6x-4y=20 and 6x+9y=-6
subtract eqn(2) from eqn(1)
6x-4y=20
6x+9y=-6 (-)
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0 -13y=26
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-13y=26
So, y=-2
Substituting y=-2 in eqn (1),
3x-2(-2)=10
3x+4=10
x=2
So, x=2 and y=-2