Question

What is the solution to the inequality below?
x2≥16

Answer 1

\[x^{2}\ge16 \]
\[\sqrt{x^{2}}\ge \sqrt{16}\]
\[x \ge \pm4\]
So, the solution lies in the interval [-4,4]

Answer 2

so would it be
'And' or 'Or' ?

Answer 3

its an "OR"

Answer 4

thanks!

Answer 5

No problem :)