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4(3-x)4/3-5=99 A. –5, 11 B. 5 C. 11 D. –11
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@tonirenee_ i think this question need the value of x. right???
yes
4 (3-x)^4/3-5=99
\[\huge 4(3-x) \times \frac{4}{3} -5=99\] Is this your equation?????
no its 4(3-x)^4/3-5=99
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\[4 (3-x)^{4/3}-5=99\]
oh!! i see
:)
someone help plz
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