If a gum-ball machine contains 22 red gum balls, 46 yellow gum balls, 14 green gum balls, and 18 orange gum balls, what is the probability that a gum ball chosen at random will be green?

A.
B.
C.
D.

Question

If a gum-ball machine contains 22 red gum balls, 46 yellow gum balls, 14 green gum balls, and 18 orange gum balls, what is the probability that a gum ball chosen at random will be green?

 		A.	
 		B.	
 		C.	
 		D.

anonymous · Answer

7/50 9/50 23/50 11/50

anonymous · Answer

you have to add them all up to get the total. so 22 + 46 + 14 + 18 would give you the total. That total you'd use as the denominator. and the numerator would be the number of green balls. that fraction would have to be simplified. then you'd get your answer.