Question

Find the fifth roots of 243(cos 240° + i sin 240°).

Answer 1

^5 the outside and *5 the innards

Answer 2

err, thats 1/5, not 5

Answer 3

its still confusing to me

Answer 4

[ k (cos a + i sin a) ]^n

k^n (cos na + i sin na)

Answer 5

243(cos 240° + i sin 240°) ^(1/5) , for 5th roots

243^(1/5) (cos 240°/5 + i sin 240°/5)

Answer 6

might have to cycle thru 1/5 2/5 3/5 4/5 5/5 to determine all the 5th roots

Answer 7

there seems to be an exponential form as well, but thats just confusing me to read :/

Answer 8

i get that the first is (cos50+isin50)

Answer 9

essentially, you are dividing a circle into 5 equal portions: 360/5 = 72

and then rotating your starting angle by 72 to get 5 complex values all together