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given the terms a1 = 5 and a 4= 14 of an arithmetic sequence what is a20
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\[T _{20}=a _{1}+(n-1)d\] we need d
now, \[a _{4}=a _{1}+(n-1)d, a _{4}=5+(4-1)d, 14=5+(3)d\] find d and you will have T 20 :)
\[T _{20}=5+(20-1)d\]
wait..... it is multiple choice it could be 62, 65,171, 185
well calculate it :) your d=3 i guess then put d in the equation and find it :)
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wait what?? so t20=5+(19)3
correct
I got 62
thats the answer :)
awesome thank you!!! can you help me with more!!! i am so behind in my math class!
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keep posting :) don't follow up
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