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Algebra 22 Online
OpenStudy (anonymous):

Can some one help me!

jimthompson5910 (jim_thompson5910):

part a) solve for x sin(30)/x = sin(120)/22

jimthompson5910 (jim_thompson5910):

part b) A = (1/2)*b*c*sin(theta) A = (1/2)*x*x*sin(120) <--- you're using the result you got for x from part a)

jimthompson5910 (jim_thompson5910):

part a) is correct

jimthompson5910 (jim_thompson5910):

i didn't say B was wrong, still checking

jimthompson5910 (jim_thompson5910):

for part B, I'm getting 69.859382571945, so that's pretty close to what you got

OpenStudy (anonymous):

oh ok!

OpenStudy (anonymous):

Great! Thanks! Can i tag you in one more!

jimthompson5910 (jim_thompson5910):

ok

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