Question

A test charge is placed at a distance of 2.0 × 10-1 meters from a charge of 5.4 × 10-8. What is the electric field at the test charge? (k = 9.0 × 109 newton·meter2/coulomb2)

:A. 1.0 × 10-2 newtons/coulomb
B. 1.2 × 103 newtons/coulomb
C. 2.5 × 104 newtons/coulomb
D. 3.5 × 10-1 newtons/coulomb
E. 5.4 × 10-8 newtons/coulomb

Answer 1

the law of electric field is\[E=\frac{ 1 }{ 4 \pi \epsilon _{0} }\frac{ q }{ r }\]