Question

(x-3)^2=4(y-2) <- for this equation. 1.)In which direction does the parabola open? 2.) What is the value of p? 3.)What is the axis of symmetry

Answer 1

PLEASE HELP! (:

Answer 2

When in doubt, try something easy.

Vertex: (3,2)
x = 0 corresponds to y = 17/4 There's a clue.
y = 0 corresponds to nothing. It doesn't exist. There is no x-intercept, so it better open UP.