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Mathematics 21 Online
OpenStudy (anonymous):

Find the number of permutations of the first 12 letters taken 3 at a time.

OpenStudy (anonymous):

@RadEn

OpenStudy (raden):

actually, it is 12P3 = ... can u evaluete the value of 12P3 ?

OpenStudy (raden):

hint : use the formula : nPr = n!/(n-r)!

OpenStudy (anonymous):

I got 1296

OpenStudy (raden):

still incorrect, try again

OpenStudy (anonymous):

ok P(12, 3) = 12! / (12 - 3)!

OpenStudy (anonymous):

12! / 9!= 12 × 11 × 10

OpenStudy (anonymous):

1,320

OpenStudy (raden):

nah, perfectly :)

OpenStudy (anonymous):

Cool thanks

OpenStudy (raden):

wlcm

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