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Find the number of permutations of the first 12 letters taken 3 at a time.
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@RadEn
actually, it is 12P3 = ... can u evaluete the value of 12P3 ?
hint : use the formula : nPr = n!/(n-r)!
I got 1296
still incorrect, try again
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ok P(12, 3) = 12! / (12 - 3)!
12! / 9!= 12 × 11 × 10
1,320
nah, perfectly :)
Cool thanks
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wlcm
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